(2x/x^2-3x)+(x+4/x-3)

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Solution for (2x/x^2-3x)+(x+4/x-3) equation:


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

x-(3*x)+(2*x)/(x^2)+4/x-3 = 0

x-3*x+(2*x)/(x^2)+4/x-3 = 0

6*x^-1-2*x^1-3*x^0 = 0

(6*x^0-2*x^2-3*x^1)/(x^1) = 0 // * x^2

x^1*(6*x^0-2*x^2-3*x^1) = 0

x^1

6-2*x^2-3*x = 0

6-2*x^2-3*x = 0

DELTA = (-3)^2-(-2*4*6)

DELTA = 57

DELTA > 0

x = (57^(1/2)+3)/(-2*2) or x = (3-57^(1/2))/(-2*2)

x = (57^(1/2)+3)/(-4) or x = (3-57^(1/2))/(-4)

x in { (57^(1/2)+3)/(-4), (3-57^(1/2))/(-4)}

x in { (57^(1/2)+3)/(-4), (3-57^(1/2))/(-4) }

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